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Table of Contents
The losing trick count is espoused by Ron Klinger, and by one of my regular partners, as a way of working out how high your side can bid when a fit has been found.
In each suit, count one loser for each of the top three cards in the suit which is not the Ace, King, or Queen.
| Void or Singleton Ace | no losers |
| Singleton or Ax | 1 loser |
| small doubleton | 2 losers |
| Kx | 1 loser |
| Axx | 2 losers |
| AQx | 1 loser |
Add your losers to partner's losers. Estimate paertner's losers by
Subtract the partnership's losers from 24. The result is the number of tricks you can expect to make.
Table of Contents
I came across this problem in an old, yellowed, newspaper clipping. Unfortunately no solution was included. It was promised "next week".
It was introduced with:
Bridge magazine in Britain has presented a double dummy problem, which is unquestionably the best ever devised.
Don't despair if you cant work it out because it has defied some of the world's best players.
(This is where I need the XML Bridge Hand DTDs, Stylesheets, etc.)
S: 8763 H: 2 D: AQ32 C: AT54 | ||
S: AQJ3 H: T98 D: 95 C: 9876 | S: T9 H: 76 D: KT876 C: KQ32 | |
S: K42 H: AKQJ543 D: J4 C: J |
West leads the 10 of trumps against 4 hearts. South to make 10 tricks.
I am not one of the world's best players, but so far it has defied me too.